Exercises Attempts
Exercise after §23
- Let and be two topologies on . If , what does connectedness of in one topology imply about connectedness in the other?
Suppose that is connected under , then the only subsets of that are both open and closed in under are the empty set and itself. Since the open sets in are contained in , it follows that the only open and closed subsets of under are also the empty set and itself, implying that is connected in .
If is connected under , it is not in general true that is connected under , as there may be other open and closed subsets of under . For example, is connected under the indiscrete topology, but not connected under the discrete topology.
- Let be a sequence of connected subspaces of , such that for all . Show that is connected.
- Let be a collection of connected subspaces of ; let be a connected subspace of . Show that if for all , then is connected.
- Show that if is an infinite set, it is connected in the finite complement topology.
- A space is totally disconnected if its only connected subspaces are one-point sets. Show that if has the discrete topology, then is totally disconnected. Does the converse hold?
- Let be a proper subset of , and let be a proper subset of . If and are connected, show that
is connected.
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Let be an indexed family of connected spaces; let be the product space
Let be a fixed point of .
(a) Given any finite subset of , let denote the subspace of consisting of all points such that for . Show that is connected.
(b) Show that the union of the spaces is connected.
(c) Show that equals the closure of ; conclude that is connected.
Let be an indexed family of connected spaces; let be the product space
Let be a fixed point of .
(a) Given any finite subset of , let denote the subspace of consisting of all points such that for . Show that is connected.
(b) Show that the union of the spaces is connected.
(c) Show that equals the closure of ; conclude that is connected.
- Let ; let and be connected. Show that if and form a separation of , then and are connected.
Exercise after §24
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(a) Show that no two of the spaces , , and are homeomorphic. [Hint: What happens if you remove a point from each of these spaces?]
(b) Suppose that there exists embeddings and . Show by means of an example that and need not be homeomorphic.
(c) Show and are not homeomorphic if .
(a) Show that no two of the spaces , , and are homeomorphic. [Hint: What happens if you remove a point from each of these spaces?]
(b) Suppose that there exists embeddings and . Show by means of an example that and need not be homeomorphic.
(c) Show and are not homeomorphic if .
- Let be a continuous map. Show there exists a point of such that .
- Let be continuous. Show that if , there is a point such that . The point is called a fixed point of . What happens if equals or ?
- Let be an ordered set in the order topology. Show that if is connected, then is a linear continuum.
- Show that if is an open connected subspace of , then is path connected. [Hint: Show that given , the set of points that can be joined to by a path in is both open and closed in .]
Exercise after §25
- Let be locally path connected. Show that every connected open set in is path connected.
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Let denote the rational poitns of the interval of . Let denote the union of all line segments joining the point to points of .
(a) Show that is path connected, but is locally connected only at the point .
(b) Find a subset of that is path connected but is locally connected at none of its points.
Let denote the rational poitns of the interval of . Let denote the union of all line segments joining the point to points of .
(a) Show that is path connected, but is locally connected only at the point . (b) Find a subset of that is path connected but is locally connected at none of its points.
- A space is said to be weakly locally connected at if for every neighbourhood of , there is a connected subspace of contained in that contains a neighbourhood of . Show that if is weakly locally connected at each of its points, then is locally connected. [Hint: Show that components of open sets are open.]
- Let be a topological group; let be the component of containing the identity element . Show that is a normal subgroup of . [Hint: If , then is the component of containing .]
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Let be a space. Let us define if there is no separation of into disjoint open sets such that and .
(a) Show this relation is an equivalence relation. The equivalence classes are called the quasicomponents of .
(b) Show that each component of lies in a quasicomponent of , and that the components and quasicomponents of are the same if is locally connected.
(c) Let denote the set , and let denote the set . Determine the components, path components, and quasicomponents of the following subspaces of :
Let be a space. Let us define if there is no separation of into disjoint open sets such that and .
(a) Show this relation is an equivalence relation. The equivalence classes are called the quasicomponents of . (b) Show that each component of lies in a quasicomponent of , and that the components and quasicomponents of are the same if is locally connected. (c) Let denote the set , and let denote the set . Determine the components, path components, and quasicomponents of the following subspaces of :
Exercise after §26
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(a) Let and be two topologies on the set ; suppose that . What does compactness of under one of these topologies imply about the compactness under the other?
(b) Show that if is compact Hausdorff under both and , then either and are equal or they are not comparable.
(a) Let and be two topologies on the set ; suppose that . What does compactness of under one of these topologies imply about the compactness under the other?
(b) Show that if is compact Hausdorff under both and , then either and are equal or they are not comparable.
- Show that a finite union of compact subspaces of is compact.
- Show that every compact subspace of a metric space is bounded in that metric and is closed. Find a metric space in which not every closed bounded subspace is compact.
- Let and be disjoint compact subspaces of the Hausdorff space . Show that there exists disjoint open sets and containing and , respectively.
- Show that if is continuous, where is compact and is Hausdorff, then is a closed map (that is, carries closed sets to closed sets).
- Show that if is compact, then the projection is a closed map.
8 (reworded). Prove that for a function where is compact Hausdorff, we have that is continuous if and only if the graph of ,
is closed in .
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Let be a closed continuous surjective map such that is compact, for each (Such a map is called a perfect map.) Show that if is compact, then is compact.
[Hint: If is an open set containing , there is a neighbourhood of such that is contained in .]
Let be a closed continuous surjective map such that is compact, for each (Such a map is called a perfect map.) Show that if is compact, then is compact.
[Hint: If is an open set containing , there is a neighbourhood of such that is contained in .]
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Let be a topological group.
(a) Let and be subspaces of . If is closed and is compact, show that is closed. [Hint: If is not in , find a neighbourhood of such that is disjoint from .]
(b) Let be a subgroup of ; let be the quotient map. If is compact, show that is a closed map.
(c) Let be a compact subgroup of . Show that if is compact, then is compact.
Let be a topological group.
(a) Let and be subspaces of . If is closed and is compact, show that is closed. [Hint: If is not in , find a neighbourhood of such that is disjoint from .]
(b) Let be a subgroup of ; let be the quotient map. If is compact, show that is a closed map.
(c) Let be a compact subgroup of . Show that if is compact, then is compact.
Exercise after §27
- Prove that if is an ordered set in which every closed interval is compact, then has the least upper bound property.
noteThis is the converse of Theorem 27.1.
This is the converse of Theorem 27.1.
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Let be a metric space with metric ; let be nonempty.
(a) Show that if and only if .
(b) Show that if is compact, for some .
(c) Define the _-neighbourhood _ of in to be the set
Show that equals the union of the open balls for .
(d) Assume that is compact; let be an open set containing . Show that some -neighbourhood of is contained in .
(e) Show the result in (d) need not hold if is closed but not compact.
Let be a metric space with metric ; let be nonempty.
(a) Show that if and only if .
(b) Show that if is compact, for some .
(c) Define the _-neighbourhood _ of in to be the set
Show that equals the union of the open balls for .
(d) Assume that is compact; let be an open set containing . Show that some -neighbourhood of is contained in .
(e) Show the result in (d) need not hold if is closed but not compact.
- Show that a connected metric space having more than one point is uncountable.
- Let be a compact Hausdorff space; let be a countable collection of closed sets of . Show that if each set has empty interior in , then the union has empty interior in . [Hint: Imitate the proof of Theorem 27.7.]
noteThis is a special case of the Baire category theorem.
This is a special case of the Baire category theorem.
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Let be the closed interval in . Let be the set obtained from by deleting its 'middle third' . Let be the set obtained from by deleting its 'middle thirds' and . In general, define by the equation
The intersection
is called the Cantor set; it is a subspace of .
(a) Show that is totally disconnected.
(b) Show that is compact.
(c) Show that each set is a union of finitely many disjoint closed intervals of length ; and show that the end points of these intervals lie in .
(d) Show that has no isolated points.
(e) Conclude that is uncountable.
Let be the closed interval in . Let be the set obtained from by deleting its 'middle third' . Let be the set obtained from by deleting its 'middle thirds' and . In general, define by the equation
The intersection
is called the Cantor set; it is a subspace of .
(a) Show that is totally disconnected.
(b) Show that is compact.
(c) Show that each set is a union of finitely many disjoint closed intervals of length ; and show that the end points of these intervals lie in .
(d) Show that has no isolated points.
(e) Conclude that is uncountable.
Exercise after §28
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Let be limit point compact.
(a) If is continuous, does it follow that is limit point compact?
(b) If is a closed subset of , does it follow that is limit point compact?
(c) If is a subspace of the Hausdorff space , does it follow that is closed in ?
noteIt is not true in general that the product of two limit point compact spaces is limit point compact, even if the Hausdorff condition is assumed. However, the (counter)examples are remarked to be sophisticated, such as the Novak space.
Let be limit point compact.
(a) If is continuous, does it follow that is limit point compact?
(b) If is a closed subset of , does it follow that is limit point compact?
(c) If is a subspace of the Hausdorff space , does it follow that is closed in ?
It is not true in general that the product of two limit point compact spaces is limit point compact, even if the Hausdorff condition is assumed. However, the (counter)examples are remarked to be sophisticated, such as the Novak space.